Mr. Goldberg's gym class does an experiment to determine their walking rates. Here are the results from the three students.
Jerome wonders how a persons walking rate could affect the amount of time it takes him or her to walk from school to the frozen yogurt shop.
A. If Terry, Jade, and Jerome all leave school together and walk toward the frozen yogurt shop at the rates given in the table, how far apart will they be after 1 minute?
1(meter)x60(seconds)=60(meters)
2(meters)x60(seconds)=120(meters)
2.5(meters)x60(seconds)=150(meters) Answer: Terry will go 60 meters, Jade will go 120 meters and Jerome will go 150 meters.
B. If the yogurt shop is 750 meters from school, how long will it take each student to walk there?
750/1=750 750/60=12 and 30 seconds
750/2=375 375/60=6 and 15 seconds
750/2.5=300 300/60=5 minutes
Answer: Terry will go 12 minutes and 30 seconds, Jade will go 6 minutes and 15 seconds, Jerome will go 5 minutes.
C. When Jerome arrives a the yogurt shop, how far away will Terry be?
12.5
-5
7.5
Terry will be 7 minutes and 30 seconds away from Jerome.
Follow Up
1. In problem 2.1, what strategies did you use to get your answers?
I used multiplication, division and subtraction.
2. Does problem 2.1 involve linear relationships? Explain why or why not.
Yes, it does because Terry, Jade and Jerome are all going at a constant rate.
Math 7D
May 28th, 2011
Jerome wonders how a persons walking rate could affect the amount of time it takes him or her to walk from school to the frozen yogurt shop.
A. If Terry, Jade, and Jerome all leave school together and walk toward the frozen yogurt shop at the rates given in the table, how far apart will they be after 1 minute?
1(meter)x60(seconds)=60(meters)
2(meters)x60(seconds)=120(meters)
2.5(meters)x60(seconds)=150(meters)
Answer: Terry will go 60 meters, Jade will go 120 meters and Jerome will go 150 meters.
B. If the yogurt shop is 750 meters from school, how long will it take each student to walk there?
750/1=750 750/60=12 and 30 seconds
750/2=375 375/60=6 and 15 seconds
750/2.5=300 300/60=5 minutes
Answer: Terry will go 12 minutes and 30 seconds, Jade will go 6 minutes and 15 seconds, Jerome will go 5 minutes.
C. When Jerome arrives a the yogurt shop, how far away will Terry be?
12.5
-5
7.5
Terry will be 7 minutes and 30 seconds away from Jerome.
Follow Up
1. In problem 2.1, what strategies did you use to get your answers?
I used multiplication, division and subtraction.
2. Does problem 2.1 involve linear relationships? Explain why or why not.
Yes, it does because Terry, Jade and Jerome are all going at a constant rate.